subject
Mathematics, 01.04.2020 05:44 darriennichole

If H=f of g and H(x) = sqrt 64 - 4x^2 which of the following cannot be the component functions f and g?

a.) f(x)=sqrt x ; g(x) = 64 - 4x^2
b.) f(x)=sqrt 64 - x ; g(x) = 4x^2
c.)f(x)=sqrt 64-4x ; g(x) = x^2
d. f(x)=sqrt 64-x^2; g(x)=4x

ansver
Answers: 3

Another question on Mathematics

question
Mathematics, 21.06.2019 14:40
Astudent simplified a rational expression as shown.
Answers: 3
question
Mathematics, 21.06.2019 15:00
Adifferent website gives the cost for the first train as £56.88 and the second train as £20.11 with a £9.50 charge for cycle storage for the whole trip. how much would the journey cost you?
Answers: 2
question
Mathematics, 21.06.2019 18:40
Juliana says that she can use the patterns of equivalent ratios in the multiplication table below to write an infinite number of ratios that are equivalent to 6: 10. which statement explains whether juliana is correct? she is correct because she can multiply 6 and 10 by any number to form an equivalent ratio. she is correct because 6: 10 can be written as 1: 2 and there are an infinite number of ratios for 1: 2. she is not correct because the multiplication table does not include multiples of 10. she is not correct because 6: 10 is equivalent to 3: 5 and there are only 9 ratios in the multiplication table that are equivalent to 3: 5.
Answers: 1
question
Mathematics, 22.06.2019 00:30
In the diagram, bc¯¯¯¯¯∥de¯¯¯¯¯ . what is ce ? enter your answer in the box.
Answers: 3
You know the right answer?
If H=f of g and H(x) = sqrt 64 - 4x^2 which of the following cannot be the component functions f and...
Questions
question
Health, 20.11.2019 22:31
Questions on the website: 13722360