Dylan has a square piece of metal that measures 16 inches on each side. He cuts the metal along the diagonal, forming two right triangles. What is the length of the hypotenuse of each right triangle to the nearest tenth of an inch?

The length of the hypotenuse of each right triangle is how many
inches?

ANSWER PLEASE ASAP♥️

Step-by-steThe area of a circle is \pi r^2πr

2

pi, r, squared.

\greenD{\pi \times 2\,\text{cm} \times 2 \,\text{cm}= 4\pi\,\text{cm}^2}π×2cm×2cm=4πcm

2

start color #1fab54, pi, times, 2, start text, c, m, end text, times, 2, start text, c, m, end text, equals, 4, pi, start text, c, m, end text, squared, end color #1fab54

Hint #55 / 6

Finally, subtract the area of the inner circle from the area of the outer rectangle.

Hint #66 / 6

\blueD{132\,\text{cm}^2} - \greenD{4\pi\,\text{cm}^2}\approx 119.43\,\text{cm}^2132cm

2

−4πcm

2

≈119.43cm

2

p explanation:

it’s supposed to be -4+45=41

step-by-step explanation:

the answer is (-8,-5)

step-by-step explanation:

the endpoint to midpoint is half the length. the length is (-2,-1) so when you are at the midpoint just add it to it to find your answer -6+(-2)= -8 and -4+(-1)=-5 so (-8,-5)