Suppose that of 900 pints of ice cream for sale, 200 are sugarless, 500 are vanilla, and 50 sugarless vanilla. What is the probability that a pint selected at random is either sugarless or vanilla? Simplify the fraction. Group of answer choices 5/6 13/18 7/9

The probability that a pint selected at random is either sugarless or vanilla is ⇒ 2nd answer

Step-by-step explanation:

If A and B are to events, then

P(A or B) = P(A) + P(B) - P(A and B)

Probability of an event =

∵ There are 900 pints of ice-cream for sale

∴ n(total) = 900

∵ 200 are sugarless

∴ n(sugarless) = 200

- Divide n(sugarless) by n(total) to find P(sugarless)

∴ P(sugarless) =

∴ P(sugarless) =

∵ 500 are vanilla

∴ n(vanilla) = 500

- Divide n(vanilla) by n(total) to find P(sugarless)

∴ P(vanilla) =

∴ P(vanilla) =

∵ There are 50 sugarless vanilla

∴ n(sugarless and vanilla) = 50

- Divide n(sugarless and vanilla) by n(total) to find P(s and v)

∴ P(s and v) =

∴ P(s and v) =

Let us use the rule above to find P(s or v)

∵ P(s or v) = P(s) + P(v) - P(s and v)

∴ P(s or v) =

∴ P(s or v) =

∴ P(sugarless or vanilla) is

The probability that a pint selected at random is either sugarless or vanilla is

an advantage of the standard deviation is that it increases as the dispersion of the data increases. e. the interquartile range is preferred when the data are not skewed or no have outliers. an advantage of the standard deviation is that it uses all the observations in its computation.

seems like d

step-by-step explanation: