Find the distance, in feet, a particle travels in its first 2 seconds of travel, if it moves according to the velocity equation v(t)= 6t2 - 18t + 12 (in feet/sec).

The particle will travel 6 feet in first 2 seconds.

Step-by-step explanation:

We have been given that a particle moves according to the velocity equation . We are asked to find the distance that the particle will travel in its first 2 seconds.

Now, we will eliminate the absolute value sign as:

Therefore, the particle will travel 6 feet in first 2 seconds.

47 - 90 = 43

43 - 180 = x

x = 137

9x