The larger of two numbers is six less than twice the smaller number. If the sum of the numbers is 42, find the numbers.

Smaller number is 16 and larger number is 26

Step-by-step explanation:

Let the smaller number be y.

The larger number is six less than twice the smaller number which is= (2×y)-6= 2y-6

The addition of the large and small number equals 42.

y + 2y - 6= 42

3y - 6 = 42

3y= 42+6

3y= 48

y= 48/3

y= 16

The smaller number is 16

The bigger number will be 2y-6= (2×16)-6 = 32-6= 26

i'm not entirely sure

step-by-step explanation:

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