Which is a equation of the line that has the slope of - 4and passes through the point (- 2, 5)?

y = - 4x - 3

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Here m = - 4, thus

y = - 4x + c ← is the partial equation

To find c substitute (- 2, 5 ) into the partial equation

5 = 8 + c ⇒ c = 5 - 8 = - 3

y = - 4x - 3 ← equation of line

The equation of the line

y = -4x - 3

Step-by-step explanation:

The equation of the line

y = mx + c

y = intercept point y

m = slope of the line

x = intercept point x

c = intercept of the line

Given

Slope = -4

Point = ( -2 , 5)

x = -2

y = 5

Insert the values into the equation

y = mx + c

5 = -4(-2) + c

5 = 8 + c

5 - 8 = c

c = 5 - 8

c = -3

Insert c into the equation of a line

y = -4x - 3

The equation of the line is

y = -4x - 3

d. bc = 12 and ef = 16

step-by-step explanation:

we are given that δabc : δdef such that .

also, it is given that

so, from the options, we need that .

a.

b.

c.  

d.

as, we can see that only option d gives the same ratio as i.e. .

hence, the possible lengths are bc = 12 and ef = 16.

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i hope this answer you! if you have any further questions or concerns, feel free to ask! : )

step-by-step explanation:

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