A soccer ball is kicked vertically from the ground with an initial velocity of 96 ft/sec.
Click "Show Your Work" and write a quadratic function, h(t), that shows
the height, in feet, of the soccer ball, t seconds after it was kicked. Use
the general equation h(t) = -16t2 + v0t + h0 where v0 is the initial velocity
and h0 is the initial height.

h(t) = - 16t² + 96t

Step-by-step explanation:

A soccer ball is kicked vertically from the ground with an initial velocity of 96 ft/sec.

So, it initial height, ft. and initial velocity feet/sec.

Now, the quadratic function, h(t), that shows the height, in feet, of the soccer ball, t seconds after it was kicked will be given by the general equation

⇒ h(t) = - 16t² + 96t + 0

⇒ h(t) = - 16t² + 96t (Answer)

37/3

step-by-step explanation:

step 1: simplify both sides of the equation.

7x+8(x+

1

4

)=3(6x−9)−8

7x+(8)(x)+(8)(

1

4

)=(3)(6x)+(3)(−9)+−8(distribute)

7x+8x+2=18x+−27+−8

(7x+8x)+(2)=(18x)+(−27+−8)(combine like terms)

15x+2=18x+−35

15x+2=18x−35

tep 2: subtract 18x from both sides.

15x+2−18x=18x−35−18x

−3x+2=−35

step 3: subtract 2 from both sides.

−3x+2−2=−35−2

−3x=−37

step 4: divide both sides by -3.

−3x

−3

=

−37

−3

x=

37

3