A professor of cognitive psychology is interested in the percent accuracy on this memory encoding task among college students. She measures the percent accuracy for 36 randomly selected students. The professor knows that the distribution of scores is normal, but she does not know that the true average percent accuracy on this memory encoding task among college students is 0.793 percent correct with a standard deviation of 0.114 percent correct.

a) Expected value of the mean = 0.793 percent

b) Standard error = 0.019 percent.

Step-by-step explanation:

Given

mean = μ = 0.793 percent

Standard deviation = σ = 0.114 percent

a) The sample mean is related to the population mean through

μₓ = μ = 0.793 percent

Hence, the expected value of the sample mean = 0.793 percent.

b) The standard error is given as

Standard error = σ/√n

where n = sample size = 36

Standard error = (0.114/√36)

Standard Error = 0.019 percent.

Hope this Helps!!!

sine

step-by-step explanation:

he earned 78.75 in interest.

step-by-step explanation: