A golf ball is hit from a hill, and its height can be modeled by h(t)= -16 + 32t + 48, where he is the
height in feet and is the time in seconds. How long will it take for the ball to reach 64 feet.

  1 second

Step-by-step explanation:

We assume your model is intended to be ...

  h(t) = -16t^2 +32t +48

Setting this equal to 64, we can find t ...

  64 = -16t^2 +32t +48

  t^2 -2t +1 = 0 . . . . . . subtract 64 and divide by -16

  (t -1)^2 = 0 . . . . . . . . factor the square

  t = 1 . . . . . . . . . . . . . the only solution

It will take the ball 1 second to reach a height of 64 feet.

since proposition states that a number is greater than 25, if is true then the number must actually be greater than 25.

this implies that all possible options, except 24, can be accepted

0.84 dang lotta people are looking for this lol or if you round up its 1 but the overall answer to that is 0.84

step-by-step explanation: