A standard deck of 52 playing cards has 4 suits. They are clubs (), diamonds (), spades (), and hearts (). The deck also has 13 different ranks. They are Ace (A), 2, 3, 4, 5, 6, 7, 8, 9, 10, Jack (J), Queen (Q), and King (K). Johnny draws 5 cards from a standard deck of 52 cards. If the cards are well shuffled, what is the probability of Johnny drawing 5 cards where 3 are one rank and 2 are another rank? (example: a 5 of clubs, a 5 of spades, a 5 of diamonds, a King of hearts, and a King of diamonds)
A. 1/108,290
B. 1/16,660
C. 1/199,920
D. 1/4,165

the answer is 375 miles

step-by-step explanation:

the answer is:

the answer is:

to solve the problem, we need to remember the quotient of power property, it's defined by the following relation:

if we have a quotienf of powers that have the same base, we need to keep the same base and subtract the exponent of the denominator power to the exponent of the numerator power.

so, we are given the expression:

then, calculating we have:

hence, the answer is:

have a nice day!

vertical asymptote .

horizontal asymptote .

step-by-step explanation:

given function is .

vertical asymptote is given by setting

denominator =0

when degree of numerator and denominator are same then divide first term of numerator by first term of denominator to get horizontal asymptote.