Determine the discriminant for the quadratic equation 0 = –2x2 + 3. based on the discriminant value, how many real number solutions does the equation have?

discriminant = b2 – 4ac

real number solutions

If you would like to know the discriminant of the quadratic equation 0 = -2x^2 + 3, you can do this using the following steps:

0 = -2x^2 + 3

0 = ax^2 + bx + c
a = -2, b = 0, c = 3

D = b^2 - 4 * a * c = 0^2 - 4 * (-2) * 3 = 0 + 4 * 2 * 3 = 24

The discriminant is 24 (positive).

If the discriminant of a quadratic equation is equal to zero (b^2 - 4ac = 0), there is one real root which is repeated. If the discriminant is positive (b^2 - 4ac > 0), there are two real roots; and if the discriminant is negative (b^2 - 4ac < 0), there are two complex roots.

Therefore, the equation has 2 real number solutions.

two

Step-by-step explanation:

It has two real number solutions I just know because I got this question right on my test. FYI Im not that good in algebra

14

step-by-step explanation:

14 x 3 = 42