F(−2)=3 f′(−2)=4 g(4)=5 g′(4)=2

The point (−2,4) lies on the curve in the xy -plane given by the equation f(x)g(y)=17−x−y , where f is a differentiable function of x and g is a differentiable function of y . Selected values of f , f′ , g , and g′ are given in the table above. What is the value of dydx at the point (−2,4) ?

answer: i think you should do the math and pay attention in class : )

step-by-step explanation:

that is truly what   think but if i get the answer i will

answer: i dont know but if you try hard you will get it right : )

step-by-step explanation:

тgє qυєѕтισи αѕкє∂: ιи тнє ѕєяιєѕ σя яєα¢тισиѕ тgαт σ¢¢υя ιи ρнσтσѕуитнєѕιѕ, ωнι¢н fσямѕ ωнєи ℓιgнт ѕтяιкєѕ α мσℓє¢υℓє σf ¢нℓσяσρнуℓℓ.

α. мσℓє¢υℓє σf ωαтєя

в.тнєє-¢αявσи ѕυgαя

¢. "єχ¢ιтє∂" єℓє¢тяσи

∂. иα∂ρн

му αиѕωєя: ιт ιѕ ¢. "єχ¢ιтє∂" єℓє¢тяσи

нσρє ι ¢συℓ∂ нєℓρ υ