The first three terms of a sequence are given. Round to the nearest thousandth (if necessary).

11, 20,29,...

Find the 30th term.

272

Step-by-step explanation:

Let a1=11

a2=20

a3=29

Formula for sequence=

an=a1+(n-1)d

an = nth term

a1= first term

n= nth position

d= common difference

We are looking for the 30th term,so our n=30

d= a2-a1

d= 20-11

d= 9

Using the formula

an= a1+(n-1)d

a30= 11+(30-1)9

a30= 11+(29)9

a30= 11+(29×9)

a30= 11+261

a30= 272

Therefore, the 30th term is 272

.19875994384

step-by-step explanation:

1699/ 8548

perimeter = 10 +  √10  units

explanation:

first, we will need to get the length of each line using the distance formula which is as follows:

distance = 

1- length of ab:

ab =   = 5 units

2- length of ac

length of ac is the same as ab = 5 units

3- length of bc:

bc =   =  √10  units

now, we can get the perimeter by adding the side lengths as follows:

perimeter = 5 + 5 +  √10

perimeter = 10 +  √10  units

hope this : )

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