Find the circumference of the figure. about

about 23.9 in

about 11.9 in

about 7.6 in

about 45.3 in

About 23.9 in

Step-by-step explanation:

Given radius (R) = 3.8

Diameter =  2R =  7.6

Circumference =  2πR

=  7.6π

=  23.876104167282

Area =  πR2

=  14.44π

=  45.364597917837

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

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step-by-step explanation: