Which function in vertex form is equivalent to f(x) = x2 + 6x + 3?
f(x) = (x + 3)2 + 3
f(x) = (x + 3)2 - 6
f(x) = (x + 5)2 + 3
f(x) = (x + 5)2 - 6

f(x) = (x+3)^2-6

Step-by-step explanation:

step-by-step explanation:

im not sure what the answer is

answer:   the paragraph proof is mentioned below.

step-by-step explanation:

given: in a δxwy where

such that, ∠wzx ≅ ∠yzx and zw≅zy

we have to prove that: segment zx is a perpendicular bisector of segment wy.

prove: since, zw≅zy ⇒ ∠wzy is a supplementary angle.

then, ∠wzy= 180°

⇒∠wzx + ∠yzx = 180° ( because xz divides ∠wzy into two parts)

but, ∠wzx ≅ ∠yzx ( given)

⇒∠wzy+∠wzy=180° ( by substitution)

⇒2∠wzy=180°

⇒∠wzy=90°

⇒∠wzy=∠yzx =90°

therefore, xz⊥wy where wz=zy

⇒zx is a perpendicular bisector of wy.