Mathematics, 03.04.2020 00:00 Tirone

Find the distance between the points (8,1) and (2,10).
Round decimals to the nearest tenth.

Answers: 1

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Answers

The nearest distance between the points (8,1) and (2,10) is 11 units, which is mentioned in and also calculated by using formula.

Step-by-step explanation:

The given is,

Two points are (8,1) (2,10)

Step: 1

By graphical method, refer the attachment,

First point (8,1)

The values of x=8 and y=1 noted in the graph

Second point (2,10)

The values of x=2 and y=10 noted in the graph

Now join the two points (8,1) and (2,10)

Measure the distance between two points, the distance is 11 units. Due to some error the value becomes 10.98 or 11.1 we need to convert the answer into nearest whole number.

( OR )

Step:1

By formula method,

Distance = $\sqrt{(x_{2} - x_{1} )^{2} +(y_{2} - y_{1} )^{2} }$ .....................(1)

Where,

(8,1) are ( $x_{1},y_{1}$ )

(2,10) are ( $x_{2},y_{2}$ )

From the equation,

= $\sqrt{(2 - 8 )^{2} +(10 - 1 )^{2} }$

= $\sqrt{(-6 )^{2} +(9 )^{2} }$

= $\sqrt{36 +81 }$

= $\sqrt{117}$

= 10.81665

≅ 11 ( Answer convert to the nearest tenth)

Distance = 11 units

Result:

The nearest distance between the points (8,1) and (2,10) is 11 units, which is mentioned in and also calculated by using formula.

Find the distance between the points (8,1) and (2,10). Round decimals to the nearest tenth.

Answer from: Quest

yes

step-by-step explanation:

Answer from: Quest

a negative exponent is translated as follows:

$a^{-m} = \dfrac{1}{a^m}$

so, we have

$\left(5^{-1}+3^{-1}+2^{-1}\right)^{-1} = \left(\dfrac{1}{5}+\dfrac{1}{3}+\dfrac{1}{2}\right)^{-1} = \left(\dfrac{6+10+15}{30}\right)^{-1}=\left(\dfrac{31}{30}\right)^{-1}=\dfrac{30}{31}$

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