The quantity R, in grams, of a certain radioactive substance decreases according to the exponential decay model dRdt=−0.05R, where t is measured in seconds. During an experiment, a scientist determines that the rate of decay of a second substance with the quantity S, in grams, can be represented by a linear model dSdt=−4, where t is measured in seconds. If at time t=0, R(0)=100 and S(0)=125, at what time t, in seconds, will there be equal quantities of both substances?

At t= 24 , in seconds, will there be equal quantities of both substances.

Given that,

The quantity R, in grams, of a certain radioactive substance decreases, according to the exponential decay model dR\dt=−0.05R, Where t is measured in seconds

The rate of decay of a second substance with the quantity S, in grams, can be represented by a linear model dS\dt=−4,

Where t is measured in seconds. If at time t=0, R(0)=100 and S(0)=125.

We have to determine,

At what time t, in seconds, will there be equal quantities of both substances.

According to the question,

Exponential decay model,

The solution of first order reaction,

Substitute the value t = 0 ,R(0)= 100,

Then,

The decay model,

That is a zero order kinetic, whose solution is:

The value at t = 0, S(0) = 125 is S₀,

Therefore,

At what time will there +ve equal quantities of both substances,

Solve the system doing R(t) = S(t),

The equation must be solved by graphing or by consecutive iterations

When t = 0 R(t) = 100 and S(t) = 125. From, that the quantities decreases.

Substitute with t = 10.

The left-hand side yields: 61 and the right-hand side yields 85.

Then, the time is greater than 10.

Substitute with t = 15

Left hand side = 47

Right-hand side = 65

t = 20

Left-hand side = 37

45

t = 25

Left-hand side = 29

Right-hand side =25

t = 24

Left-hand side =3 0

Right hand side = 29

Hence, 24 seconds is a satisfactory solution.

The graph attached shows that the intersection point is at t ≈ 23.548 seconds, confirming that 24 seconds is the best solution rounded to an integer number.

Hence, At t= 24 , in seconds, will there be equal quantities of both substances.

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Explanation:

1. Quantiy R

Decay model:

That is a first order reaction, whose solution is:

The value at t = 0, R(0) = 100 is R₀.

Thus, the law is:

2. Quantity S

Decay model:

That is a zero order kinetic, whose solution is:

The value at t = 0, S(0) = 125 is S₀

Thus, the law is:

3. At what time will there ve equal quantities of both substances?

You must solve the system doing R(t) = S(t)

That equation must be solved by graphing or by consecutive iterations

Note that when t = 0 R(t) = 100 and S(t) = 125. From, that the quantities decreases.

Subsitute with t = 10.

Then, the time is greater than 10.

Substitute with t = 15

t = 20

t = 25

t = 24

Hence, 24 seconds is a satisfactory solution.

The graph attached shows that the intersection point is at t ≈ 23.548 seconds, confirming that 24 seconds is the best solution rounded to an integer number.

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