Which equation represents a line that passes through (-9, -3) and has a slope of -6?
y-9=-5(x – 3)
y+9= -6(x + 3)
y-3--5(x – 9)
y+3=-6[X + 9)

  y +3 = -6(x +9)

Step-by-step explanation:

The point-slope form of the equation of a line is ...

  y -k = m(x -h)

for a line with slope m through point (h, k).

You want the line with slope -6 through point (-9, -3), so its equation is ...

  y -(-3) = -6(x -(-9))

  y +3 = -6(x +9) . . . . . matches the last choice

positive

step-by-step explanation:

the quadrant is facing upwards

step-by-step explanation:   divide the numerator by the denominator to get the decimal

it would still be 193

if divide by 100 then 1.93

i am not sure