What are the possible number of positive real, negative real, and complex zeros of f(x) = 4x3 + x2 + 10x – 14?

a.) positive real: 1. negative real: 0. complex: 2
b.) positive real: 1. negative real: 2 or 0. complex: 2 or 0
c.) positive real: 2 or 0. negative real: 1. complex: 2 or 0
d.) positive real: 2 or 0. negative real: 2 or 0. complex: 1

f(0) = -14 is easy to calculate. You can actually note that other than -14, every coefficient are positive, so f will be increasing for x > 0 and it will eventually hit zero, turn positive, and continue on getting larger. So it has exactly 1 positive real root. So this means that it only has exactly 1 positive real root and these would be the possible numbers of positive real, negative real, and complex zeros of f(x) = 4x3 + x2 + 10x – 14.

Positive Real: 1.

Negative Real: 2 or 0.

Complex: 2 or 0 

The correct answer between all the choices given is the second choice or letter B. I am hoping that this answer has satisfied your query and it will be able to help you in your endeavor, and if you would like, feel free to ask another question.

You can find the area of a rectangle by multiplying the length and height. so multiply 1/2*7/4(which is the simpler version of 1 3/4) and you get 7/8 as your answer.

Iam not sure , but probably 750 or 7.5