Suppose that Mike selects a ball by first picking one of two boxes at random and then selecting a ball from this box at random. The first box contains 4 red balls and 3 blue balls, and the second box contains 2 red balls and 5 blue balls. What is the probability that Mike picked a ball from the second box if he has selected a red ball

i think it is c, not positive though

step-by-step explanation:

the answer is b: 18

step-by-step explanation:

use the pythagorean theorem to .

a^2+b^2=c^2

plug 18 for "r"

the 2 legs are 18 and 24

18^2+24^2=c^2

324+576=c^2

900=c^2

c=30

30-12=18

18 is the radius

: )

step-by-step explanation:   divide the numerator by the denominator to get the decimal

it would still be 193

if divide by 100 then 1.93

i am not sure