N a study of the accuracy of fast food drive-through orders, Restaurant A had 314 accurate orders and 61 that were not accurate. a. Construct a 90% confidence interval estimate of the percentage of orders that are not accurate. b. Compare the results from part (a) to this 90% confidence interval for the percentage of orders that are not accurate at Restaurant B: 0.147less thanpless than0.206. What do you conclude?

a. 0.1576<p<0.2310

b. The two restaurants likely have similar order rates which are inaccurate.

Step-by-step explanation:

a. We first calculate the proportion, :

-We use the z-value alongside the proportion to calculate the margin of error:

The confidence interval at 90% is then calculated as:

Hence, the confidence interval at 90% is [0.1576,0.2310]

b. From a above, the calculated confidence interval is 0.1576<p<0.2310

-We compare the calculated CI to the stated CI of 0.147<p<0.206

-The two confidence intervals overlap each other and have the same value for 0.1576<p<0.206

-Hence, we conclude that the two restaurants likely have similar order rates which are inaccurate.

hope it you

step-by-step explanation:

sin(7pi/6 - pi/3)  

= sin(7pi/6 - 2pi/6)  

= sin(5pi/6)  

= sin(pi - pi/6)  

= sin(pi/6)  

= 1/2  

sin 7pi/6 - sin pi/3  

= sin (pi + pi/6) - sin pi/3  

= -sin pi/6 - sin pi/3  

= -1/2 - sqrt(3)/2  

= -(1+sqrt(3))2

y/x of point b= y/x of point a

step-by-step explanation:

(i got the same question, this was the correct answer.)