What is the solution for the equation
5/3b^3-2b^2-5=2/b^3-2?

b= -4 and b=0
b= -4
b= 0 and b=4
b= 4

b=0.46005 approx

Step-by-step explanation:

ugh its to messy just solve it like a quadratic

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

hello umm i don't understand your question can you explain it more pls

step-by-step explanation: