Pat's average weekly income from her part time job was 15% more in September than it was in July. her average weekly income in July was 10% less than it was in August. if her average weekly income in September was $207, what was her average weekly income in August?

Her average weekly income in August was $200.

Step-by-step explanation:

To find the income in july :

Given that,

Let,

'x' be the 100% of income she got in July.

Therefore, the income $207 in September is 115% of x.

⇒ 115% of x = 207

⇒ 1.15 × x = 207

⇒ x = 207 / 1.15

⇒ x = 180

∴ Her average weekly income in July was $180.

To find the income in August :

Given that,

Let,

'y' be the 100% of income she got in August.

Therefore, the income $180 in July is 90% of y.

⇒ 90% of y = 180

⇒ 0.9 × y = 180

⇒ y = 180/0.9

⇒ y = 200

∴ Her average weekly income in August was $200.

her average weekly income in August was $200 .

Step-by-step explanation:

Let in July income was x , So in September :

⇒

According to question , her average weekly income in September was $207 i.e.

⇒

⇒

⇒

⇒

Now , average weekly income in July was 10% less than it was in August , let income of august = y,  i.e.

Income in august =

⇒

⇒

⇒

Therefore , her average weekly income in August was $200 .

the answer is b: 18

step-by-step explanation:

use the pythagorean theorem to .

a^2+b^2=c^2

plug 18 for "r"

the 2 legs are 18 and 24

18^2+24^2=c^2

324+576=c^2

900=c^2

c=30

30-12=18

18 is the radius

: )