A 12-foot ladder leans against the wall; the base of the ladder is 2 feet away from the wall. To the nearest tenth of a foot, how far up the wall does the ladder reach?

Solution:

The ladder, wall and base of the ladder from wall forms a right angled triangle

Length of ladder forms the hypotenuse

Length of ladder = 12 foot

base of the ladder from wall = 2 feet

To find: height of wall

By pythagoras theorem.

Where,

"c" is the Length of ladder

"a" is the base of the ladder from wall

"b" is the height of wall

Substituting the values,

Thus, the ladder will reach a height of 11.8 feet on wall

25/4

step-by-step explanation:

call segment cd's length x. because dc and ab are parallel, angle acd and cab, so triangles adc and abc are similar and we can set up the equation x / ac = ac / ab, or x / 5 = 5 / 4 and x = 25/4.

40 is the final : )