An object is launched straight into the air. The projectile motion of the object can be modeled using h(t) = 96t – 16t2, where t is the time since launch and h(t) is the height in feet of the projectile after time t in seconds.

answer: expected value of x = 1.0

step-by-step explanation:

p(x=0) = 0.25

p(x=1) = 0.50

p(x=2) = 0.25

expected value for x = 0×0.25 + 1×0.5 + 2×0.25 = 1.0

for me what is finding a good play list and going out because i can not lay down and relax so i usually go to a coffee shop. i also use the gum trick and this actually works. another advice is highlighting subjects it really does me remember certain things

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answer: i wpould go with c

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if she was to only spend a dollar she can get 1lb

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