3 dice, one with 4 sides, 5 sides, and 6 sides. Each dice is fair and has faces (1, 2, ... n) where n is the number of sides. Tim proceeds as follows: he rolls each die one at a time (starting with the four sided, then five, then six). However, if Tim ever rolls more than a three he stops rolling the dice. Let X be the sum of all the dice Tim rolled. 1. Compute E[X]. 2. Compute P(A). Where A represents the event that Tim rolled a five with one of the die.

i just took the test, the correct answer is .. 31.5 in.

example 2 – simplify: step 1: completely factor both the numerators and denominators of all fractions. step 2: change the division sign to a multiplication sign and flip (or reciprocate) the fraction after the division sign; essential you need to multiply by the reciprocal. step 3 : cancel or reduce the fractions.

cosine

step-by-step explanation:

option 3 . (5x + 1) - (-10x + 6)

step-by-step explanation:

option 1 :

(4x + 3) + (-9x + 4)

or 4x+3 -9x + 4

or -5x + 7

option 2

(x - 2) - (6x - 9)

or x-2-6x + 9

or -5x + 7

option 3

(5x+ + 6)

or 5x + 1 + 10x -6

or 15x -5

option 4

-4x+2x+7-3x

-7x + 2x + 7

-5x + 7

hence only option 3 did   not satisfy the given simplify expression.