What is the prime factorization of 200?

2 2 × 5 3
2 3 × 5 2
2 4 × 5
2 × 5 4

2^3 * 5^2

Step-by-step explanation:

We need to break 200 down into prime numbers

200 = 20*10  These are not prime

       = 4*5  * 2*5    The 4 is not prime

       = 2*2*5  * 2*5  This is prime

Rearranging

       = 2*2*2*5*5

       = 2^3 * 5^2

the value of v.w= -12.

step-by-step explanation:

we are given three vector r,v and w as:

r = < 5, -5, -2> ; v = < 2, -8, -8> ; w = < -2, 6, -5>

we know that r,v and w could also be represented as:

r=5i-5j-2k

v=2i-8j-8k

and w= -2i+6j-5k

where i,j and k are the unit vectors of x,y and z-axis respectively.

also we know that it has the following property:

i.i=1 ; j.j=1; k.k=1

and i.=j.i=i.k=k.i=j.k=k.j=0

i.e. when we multiply two vectors or we find it's dot product we need to only multiply the components of x coordinates with each other; y with each other and z with each other.

hence, v.w= (2i-8j- -2i+6j-5k)

                  = 2×(-2)+(-8)×(6)+(-8)×(-5)

                  = -4-48+40

                  = -12

hence, v.w= -12

i you goofed up when writing this, because hnot is not a word minusf is not either. i cannot answer   because of that.

step-by-step explanation: