We started something new and I'm competely lost

Given:

Triangle ABC is similar to triangle XYZ.

The measures of the sides are AB = 6 cm, BC = 18 cm and XY = 12 cm

We need to determine the measure of side YZ.

Measure of YZ:

Since, ABC and XYZ are similar triangles, by using similar triangles property, we have;

Let the length of YZ be x.

Substituting the values, we get;

Cross multiplying, we get;

Dividing both sides by 6, we have;

Thus, the value of x is 36.

Hence, the measure of the side YZ is 36 cm.

to find the perimeter of the rectangle this is the expression:

x-9+x-9+3x-4+3x-4=138

if we simplify it:

8x-26=138

remember, 138 is what it all adds up to

the length is 11.5cm

the width is 57.5cm

the area is 661.25cm^2

the answers might not be correct use at own risk

answer:

given the linear inequality :

add 2y to both sides we get;

simplify:

add 12 to both sides of an equation;

simplify:

divide both sides by 2 we get;

or

the related equation for the inequality equation [1] is;

y-intercepts defined as the graph crosses the y-axis.

substitute x =0 in [2] to solve for y;

y = 6

x-intercepts defined as the graph crosses the x-axis.

substitute value y = 0 to solve for x;

subtract 6 from both sides we get

multiply both sides by 2 we get;

or

x = -12

now, plot these point (0, 6) and (-12, 0) on graph as shown below and shade the graph below the solid line.