To write 11x2+17x−10 in factored form, Diego first listed pairs of factors of -10. (_+5)(_+-2) (_+2)(_+-5) (_+10)(_+-1) (_+1)(_+-10) Use what Diego started to complete the rewriting. Only one of the factored forms needs to be used and completed.

The factored form of the polynomial is 11*(x+2)*(x-5/11). The root found was r = -2

Step-by-step explanation:

If you take a positive value of x, you will most likely obtain positive results, since 11x² + 17x ≥ 11 + 17 = 28 for x ≥1, which means that 11x²+17x-10 ≥ 28-10 = 18 > 0.

Therefore, we prove with negative values.

Therefore, -2 is a root. We can find the other knowing that

p(x) = 11*(x-r₁)*(x-r₂) = 11*(x-(-2)) * (x-r₂) = 11*(x+2)*(x-r₂)

The independent term is 11*2*(-r₂) = -22r₂ = -10

thus, r₂ = -10/-22 = 5/11.

Therefore, p(x) = 11*(x+2)*(x-5/11)

center= (-2,0)

radius= sqrt2/2

step-by-step explanation:

so, converting firstly the mixed fractions to improper fractions and then "adding".