Question 10 [10 points] The number of frogs in a pond increases continuously at a rate proportional to the number present. There are 150 frogs present at a given time and 530 present 4 hours later. (a) How many frogs will there be 10 hours later the initial time? (b) How long will it take for the population to reach 10000 frogs?

a) 1325 frogs b)75.47 hours

Step-by-step explanation:

start = 150 frogs

after 4 hours = 530

1) figure out how many frogs per hour 530/4 = 132.5 frogs per hour

2) 10 hours after initial time * 132.5 frogs = 1325 frogs

3) Time to reach 10000 frogs is => 10000 / 132.5 = 75.47 hours

just do 5.2 + 2 ( 7.2) and 1/3 x 3 (.9) and youv'e got your equation. 0.9( 9/10) + 7.2 ^2 = 16.4 hope i could !

step-by-step explanation: