Mr. Williams is building a sand box for his children. It cost $228 for the sand if he builds a regular-sandbox with dimensions 9‘ x 6‘. How much will the same cost if he decides to increase the size to 13 1/2‘ x 9‘?

It will cost $512.73

Step-by-step explanation:

9 in by 6 in sandbox cost $228

i.e., 9*6 = 54 in²

54 in² cost $228

1 in² will cost $228/54

≈ $4.22

If the new dimension is 13 1/2 in by 9 in

then area will be 13 1/2*9

27*9/2 = 121.5 in²

The cost of 121.5 in² will be

121.5*4.22 = $512.73

answer: i think it is (1,-2)