The new office building downtown has 3 large concrete cylindrical columns in front. The columns are 20 feet tall with a diameter of 4 feet. About how much concrete was used to manufacture the three columns

753.982 ft^3

Step-by-step explanation:

Use the fomula for the area of a circle:

4/2=2

2^2=4

4 x pi =12.566 ft ^2

Multiply that by the height of the column:

12.566 x 20=251.327 ft^3

And that by the number of columns:

251.327 x 3=753.982 ft^3

Have a great day, and mark me brainliest if I am most helpful!

the volume of concrete to be used is 753.6 ft³

Step-by-step explanation:

Since the columns are cylindrical, we would determine the volume of each column by applying the formula for determining the volume of a cylinder which is expressed as

Volume = πr²h

Where

π represents a constant whose value is 3.14

r represents the radius of the columns

From the information given,

Diameter = 4 feet

Radius = diameter/2 = 4/2 = 2 feet

Height = 20 feet

Volume = 3.14 × 2² × 20 = 251.2 ft³

Volume of the 3 concrete columns is

251.2 × 3 = 753.6 ft³

0.02

step-by-step explanation:

time of 9 192 631 770 periods of the radiation corresponding to the transition between the 2 hyperfine levels of the ground state of the caesium 133 atom at 0 k (but other seconds are sometimes used in astronomy)