Please help me with RSM questions!
Simplify:

(−2)∙(2a−b)+3(a+b)

(−5)∙(a−2b+3c−4d)−(−3)∙(4a−3b+2c−d)

I'm giving 50 points if you answer correct!

#1

Let's simplify step-by-step.

−2(2a−b)+3(a+b)

=(−2)(2a)+(−2)(−b)+(3)(a)+(3)(b)

=−4a+2b+3a+3b

=−4a+2b+3a+3b

=(−4a+3a)+(2b+3b)

=−a+5b

#2

=(−5)(a)+(−5)(−2b)+(−5)(3c)+(−5)(−4d)+12a+−9b+6c+−3d

=−5a+10b+−15c+20d+12a+−9b+6c+−3d

=−5a+10b+−15c+20d+12a+−9b+6c+−3d

=(−5a+12a)+(10b+−9b)+(−15c+6c)+(20d+−3d)

=7a+b+−9c+17d