Given Set P: 3, 4, 7, 8, 8 and Set Q: 0, 0, 1, 1, 3, 7.
Calculate the mean and mean absolute deviation for both sets. Then, answer the following questions.

How many data points in Set Q are closer than one mean absolute deviation from the mean of Set Q?
How many data points in Set P are further than two mean absolute deviations from the mean of Set P?
Find the difference between the two means. How does this difference relate to the mean absolute deviation of each set? For example, is it the same as the mean absolute deviation, twice as much, half as much, etc?

$30.32

step-by-step explanation:

65.00*.12=2.80

65.00-2.80=57.20

57.20*1.06=60.632

60.632/2=30.316

option c) graph of line going through 1, 4 and 3, 10

step-by-step explanation:

let y equal to margo's coin collection

let x equal to number of years

at the begining x=0, y=1 → point=(x,y)→point=(0,1)

she adds 3 coins per year, then y=1+3x

at x=1, y=1+3(1)=1+3→y=4→point=(x,y)→point=(1,4)

at x=3, y=1+3(3)=1+9→y=10→point=(x,y)→point=(3,10)

the graph of line going through (1, 4) and (3, 10), then the option c is the correct.

one set of data has more variation than the other. hope this !

the answer is 1030 it's very simple math.