Find the probability of at least 2girls in 6 births assume that the male and female birth are equally likely and that tha births are independent events

57/64

Step-by-step explanation:

exactly 6 boys:  (1/2)^6  

exactly 5 boys:  6*(1/2)^6  G GB (and the 4 other slots the girl can fall)

at least 2 girls is equal to all other scenarios (where there are not 5 or 6 boys)

= 1 - [exactly 6 boys] - [exactly 5 boys]

= 1 - (1/2)^6 - 6*(1/2)^6

= 1 - 7*(1/2)^6

= 1 - 7(1/64)

= 1 - 7/64

= 57/64