Ryan needs to choose out of the 5 chores for afterschool. If he is equally likely to choose the chores, what is the probability he will choose the first 2 on list

 0.2

Step-by-step explanation:

Number of ways to select r things out of n things =

Then , Total number of ways to select 2 out of 5 chores =

Number of ways to selecting first 2 on list = 2 (either he choose top on the list first then second , or second person first then topper)

Now , the probability he will choose the first 2 on list =

Hence, the probability he will choose the first 2 on list is 0.2.

answer: integers are just whole numbers: positive, negative, and zero.

i = {-∞, -2, -1, 0, 1, 2, 3, ∞}

let x = 1st integer

let y = 2nd integer

x = 3y + 17   {equation 1}

xy = -24         {equation 2}

substitute 3y+17 in place of x n equation 2

and solve for y.

(3y+17)y = -24

3y2 + 17y = -24

3y2 + 17y + 24 = 0

from quadratic equation:

y = [-17±√(172-4(3)(24))]/(2(3))

y = (-17 ±√1)/6

y = (-17+1)/6   or     y = (-17-1)/6

y = -16/6           or     y = -18/6

y = -2 2/3         or   y = -3

since we are dealing with

y = -3

x = 3y+17 = -9+17 = 8

the integers are -3, 8

step-by-step explanation: