In triangle JKL, the bisector of angle J divides KL into XK with length y + 3 and XL with length 2y. If JK = 12 and JL = 16, what is the length of XK? *

The length of XK = 12.7

Step-by-step explanation:

Given that

JK = 12 , JL = 16 , KX = y + 3  , XL = 2y

From the Δ JKX

 ----- (1)

From the Δ JXL

---------- (2)

From Equation (1) & (2) we get

144 - (

By solving above equation we get

y = 9.7

Therefore the length of XK = y + 3 = 9.7 + 3 = 12.7

so we may be on two differnt triangles since he didnt involve the picture like he shouldve but the answer is 9 in. ill show proof:

Step-by-step explanation:

option (b) is correct

step-by-step explanation:

to find the solution of this system, we need to convert it into reduced row-echelon form. we have,

after applying row operations r2 -> r2/2 and r3 -> r3/3, we get,

$75.00

step-by-step explanation:

i = prt

i = 1,5000 * 0.025 * 2

i = 75