Please help me :) I’ll give brainliest

a)3x+33=90, x=19 b)52, 38

Step-by-step explanation:

a)

so x+33+2x=90

which simplifies to 3x+33=90

Now we need to solve that equation.

3x+33=90

x+11=30

x=19

b)

angle 1 is x+33.

19+33=53

angle 2 is 2x

19*2=38

Part A: (x+33) + (2x) = 90

Part B: mAngle 1= 52, mAngle 2= 38

Step-by-step explanation:

Part A:

To write an equation, we first must understand what we are trying to describe/equal to. In the figure, we can see a box in the bottom left corner. This signifies that the angle is a right angle, which equals to 90 degrees.

In the directions, it gives us the measurement of the two angles that make up that 90 degree angle, which is angle 1 and angle 2.

Angle 1 equals to x+33 and angle 2 equals to 2x.

Thus, we can say (x+33) + (2x) equals to 90 degrees.

Part B:

Now, we must solve for the angles. Simply, we must find the value of "x."

To do that, we add like terms on both sides of the equation:

(x+33) + (2x) = 90 becomes 3x + 33 = 90

There are two ways you can proceed from here: factor and solve, or simply the old fashioned way: elimination.

Factor and solve:

3x + 33 = 90 becomes 3(x+11)=3(30). I simply factored the LCD (largest common denominator) from both sides. If we multiply it out, we'll return to 3x + 33 = 90 We then proceed to divide both sides by three, giving us x+11=30. x equals 19.

Elimination:

3x + 33 = 90 becomes 3x=57. I simply subtracted 33 from both sides. Then, isolate x by dividing by three, and x equals 19.

We aren't done just yet. Now, since we know what x equals, we must substitute 19 for x in angle 1 and angle 2.

(x+33) + (2x) = 90

(19+33) + [2(19)] = 90

52 + 38 = 90

So, measure of angle 1 is 52, and measure of angle 2 is 38.

Let me know if you have any questions.  

27 +27 or 27times 2=54

the diffrence is 0

df =

both have same length