What is the vertex of g(x)=3(x+1)^2-12

 (-1,-12)

Step-by-step explanation:

This equation is in vertex form

g(x)=a(x-h)^2+k  where( h,k) is the vertex

g(x)=3(x+1)^2-12

Rewriting

g(x)=3(x- -1)^2+ -12

So the vertex is

    (-1,-12)

a

step-by-step explanation:

when a number is between two straight lines it means the absolute value.

to find absolute value you need to know how many numbers is that number away from 0.

when finding absolute value the number will always come out positive

so absolute value of -3 is 3

absolute value of 3/2 is 3/2

absolute value of -2 is 2

absolute value of 3.5 is 3.5

absolute value of -1 is 1

now put these numbers in order:

a)   |-1|, |3/2|, |-2|, |-3|, |3.5|