Which graph is the sequence defined by the function f(x) = 3(2)x-1?
A.
On a coordinate plane, 5 points are plotted. The points are (0, 2), (1, 6), (2, 18), (3, 54), (4, 162).
B.
On a coordinate plane, 5 points are plotted. The points are (1, 2), (2, 6), (3, 18), (4, 54), (5, 162).
C.
On a coordinate plane, 6 points are plotted. The points are (0, 3), (1, 6), (2, 12), (3, 24), (4, 48), (5, 96).
D.
On a coordinate plane, 5 points are plotted. The points are (1, 3), (2, 6), (3, 12), (4, 24), (5, 48).

On a coordinate plane, 5 points are plotted. The points are (1, 3), (2, 6), (3, 12), (4, 24), (5, 48).

Given that,

We have to determine,

Which graph is the sequence defined by the function?

According to the question,

To determine the graph is the sequence defined by the function following all the steps given below.

On a coordinate plane, 6 points are plotted.

1. Substitute the point x = 0 in the function,

2. Substitute the point x = 1 in the function,

3. Substitute the point x = 2 in the function,

4. Substitute the point x = 3 in the function,

5. Substitute the point x = 4 in the function,

6. Substitute the point x = 5 in the function,

Hence, On a coordinate plane, 5 points are plotted. The points are (1, 3), (2, 6), (3, 12), (4, 24), (5, 48).

For more details refer to the link given below.

link

D.

On a coordinate plane, 5 points are plotted. The points are (1, 3), (2, 6), (3, 12), (4, 24), (5, 48).

Step-by-step explanation:

f(x) = 3 × 2^(x - 1)

x = 1, f(x) = 3 × 2^0 = 3

answer: 43/157

this is the answer and if you try to prove me wrong your a meanie

hope this .

r3t40