Write an equation of the circle with center (3, -6) and radius 5.

answer

(x-3)^2 + (y+6)^2 = 25

set up equation

the equation of a circle is (x - centerx)^2 + (y - centery)^2 = r^2

values

from the point (3,6) we know that centerx = 3 and centery = -6

since the radius is 5, r^2 = 5^2 = 25

plug in values

now that we have all the values, we plug them into (x - centerx)^2 + (y - centery)^2 = r^2

(x - centerx)^2 + (y - centery)^2 = r^2

(x - 3)^2 + (y-(-6))^2 = 25

(x-3)^2 + (y+6)^2 = 25

x² + 3x + 7 = 0       [ax² + bx + c]

a = 1

b = 3

c = 7

quadratic formula:

    (+/- is this ±)

plug in the numbers into the variables

your answer is a

false

step-by-step explanation:

false : it can not go to 9 the highest that part can go is 7

here is your proof