The measure of angle A is 15°, and the length of side
BC is 8. What are the lengths of the other two sides,
rounded to the nearest tenth?
AC =
00
5) Intro
Done

Part 1)

Part 2)

Step-by-step explanation:

The picture of the question in the attached figure

Part 1

Find the length side AB

we know that

----> by SOH (opposite side divided by the hypotenuse)

substitute the given values

solve for AB

Part 2

Find the length side AC

we know that

----> by TOA (opposite side divided by the adjacent side)

substitute the given values

solve for AC

rx and sx

step-by-step explanation:

37/3

step-by-step explanation:

step 1: simplify both sides of the equation.

7x+8(x+

1

4

)=3(6x−9)−8

7x+(8)(x)+(8)(

1

4

)=(3)(6x)+(3)(−9)+−8(distribute)

7x+8x+2=18x+−27+−8

(7x+8x)+(2)=(18x)+(−27+−8)(combine like terms)

15x+2=18x+−35

15x+2=18x−35

tep 2: subtract 18x from both sides.

15x+2−18x=18x−35−18x

−3x+2=−35

step 3: subtract 2 from both sides.

−3x+2−2=−35−2

−3x=−37

step 4: divide both sides by -3.

−3x

−3

=

−37

−3

x=

37

3