Of the 98 patients that visited Doctor McClary's office this week, 25 described themselves as former smokers, F, and 11 described themselves as current smokers, C. How many patients were current or former smokers, |C∪F|? What is the probability that a randomly-selected patient is a current or former smoker, P(C∪F)? Express your answer to three decimal places.

Number of current or former smokers is 36

AND

The probability of a randomly selected patient is a current or former smoker is 0.367

Step-by-step explanation:

The question says that, Of the 98 patients that visited Doctor McClary's office this week, 25 described themselves as former smokers, F, and 11 described themselves as current smokers, C.and we are now asked to find the number of patients that are current or former smokers, |C∪F|? And the probability that a randomly-selected patient is a current or former smoker.

Out of 98 patients, 25 are former smokers,denoted by the character, F

And 11 of these patients are also current smokers,also denoted by C

*Number of smokers-both current and former- that visited doctor McClary's office is

C + F which is 11 + 25 = 36 patient(smokers)

---The second question says to find out the probability of randomly selecting a former or current smoker.

*Since there are a combined 36 smokers(both current and former) out of 98 patients that visited a doctor,the probability of selecting a smoker whether current or former will be

36/98 = 0.367

2160ft3

step-by-step explanation:

i think the correct option is the second option.