A student records the number of hours that they have studied each of the last 23 days. They compute a sample mean of 2.3 hours and a median of 2.5 hours. When they review their data, they notice that the maximum value was recorded as 10 hours and it should have been 14. they fix this error. When compare to origional dataset, did the IQR:.1. Increase2. Decrease3. Stayed the same4. There is no way to tell without actually seeing the data

the standard deviation increases

Step-by-step explanation:

Let x₁ , x₂, .   .   .  , x₂₃ be the actual data observed by the student

The sample means  = x₁  +  x₂  +  .   .   .  , x₂₃ / 23

= 2.3hr

⇒

let x₁ , x₂, .   .   .  , x₂₃  arranged in ascending order

Then x₂₃ was 10  and has been changed to 14

i.e x₂₃ increase to 4

Sample mean  

therefore, the new sample mean is 2.47

2) For the old data set

the median is values

when we use the new data set only x₂₃ is changed to 14

i.e the rest all observation remain unchanged

Hence, sample median = remain unchange

sample median = 2.5hrs

The Standard deviation of old data set is calculated

The new sample standard sample deviation is calculated as

Now, when we compare (1) and (2)  the square distance between each observation xi and old mean is less than the squared distance between each observation xi and the new mean.

Since,

(xi - 2.3)²  ∑ (xi - 2.47)²

Therefore , the standard deviation increases

these sign is used to tell weather the number is greater or less than the number   <   or >     but this sign means its equal =    

hope this you and

step-by-step explanation:

66.666666667%

step-by-step explanation:

divide 150 by 100

divide 100 by 1.5

there you go!

decreased by 33.333333334%