Please help me with this

1)

a. 18x²-8

b. f'(x) = 6x²+20x+1

c.

2)

a.[2(x-1)-2x]/(x-1)²

b. [(4x+3)(x²+1)-(2x)(2x²+3x-2)]/(x²+1)²

Step-by-step explanation:

1)

a. f(x) = 2x(3x²-4)

f'(x) = 2(3x²-4)+(6x)(2x)

f'(x) = 6x²-8+12x² = 18x²-8

b. f'(x) = (2x²+1)+(4x)(x+5)

f'(x) = 2x²+1+4x²+20x

f'(x) = 6x²+20x+1

c. f'(x) = + =

2.

a. f'(x) = [2(x-1)-2x]/(x-1)²

b. f'(x) = [(4x+3)(x²+1)-(2x)(2x²+3x-2)]/(x²+1)²

18

step-by-step explanation:

draw the shape and you will see that f and k are actually at adjacent vertices (points of the hexagon that are neighboring).   so find the distance between (1,2) and (4,2).   that is easy since (1,2) and (4,2) is just a vertical distance to count, which is 3.   it is a regular polygon which means all sides are congruent.   you have 6 sides (hexa) so multiply 6 by 3 to receive 18.

a

step-by-step explanation:

strong negative correlation