The area of a rectangular wall in a classroom is 280 square feet. Its length is 2
feet shorter than three times its width. Find the width of the wall of the
classroom.

The width of the wall of the  classroom is 10 feet and this can be determined by forming the quadratic equation.

Given :

The area of a rectangular wall in a classroom is 280 square feet. Its length is 2  feet shorter than three times its width.

The following steps can be used in order to determine the width of the wall of the  classroom:

Step 1 - Let the length of the rectangular wall be 'l' and the width of the wall be 'w'.

Step 2 - According to the given data the area of the rectangular wall is given by:

   --- (1)

Step 3 - Now, it is also given that the length of the wall is 2  feet shorter than three times its width that is:

l = 3w - 2

Step 4 - Substitute the value of 'l' in the equation (1).

280 = w(3w - 2)

Step 5 - So, (w = 10) is one of the factors of the above quadratic equation.

So, the width of the wall of the  classroom is 10 feet.

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The width of the classroom is 10 feet, if the area of a rectangular wall in a classroom is 280 square feet and Its length is 2  feet shorter than three times its width.

Step-by-step explanation:

The given is,

                   Area of rectangular is 280 square feet

                   Length is 2  feet shorter than three times its width

Step:1

            Formula for area of rectangular,

                                    ..............................(1)

           Where, w - width of the rectangle

                        l - Length of the rectangle

          From the given,

          Let, x- width of the rectangle

                     w = x...........................................................(2)

                      ...................................................(3)

          (  Length is 2  feet shorter than three times its width )

          Equation (1) becomes,

                           =

          Solution of the above equation,

                        x = 10 feet

Step:2

          Equation (2) becomes,

                             w = 10 feet

          Equation (3) becomes,

                             l = 28 feet

Step:3

         Check for solution equation (1) becomes,

                        280 = (28) (10)

                        280 = 280

Result:

            The width of the classroom is 10 feet, if the area of a rectangular wall in a classroom is 280 square feet and Its length is 2  feet shorter than three times its width.

your answer would be b

step-by-step explanation:

i think is 3 and 6. this took me 10 min to think.hope to and hope that my answer is brainliest.(follow me )