Assume that the heights of American men are normally distributed with a mean of 69.0 inches and a standard deviation of 2.8 inches. The U. S. Marine Corps requires that men have heights between 64 and 78 inches. Find the percent of men meeting these height requirements.

A) 31.12%
B) 99.93%
C) 3.67%
D) 96.26%

The percent of men heights between 64 and 78 inches = 96.22

Step-by-step explanation:

Given -

Mean height = 69.0

Standard deviation = 2.8

Let X be the height of american man

The percent of men heights between 64 and 78 inches =

=

                          =      Put  []

                          =     Using z table

                           = 0.9993 - .0370

                           =  .9622

                           =  96.22

360/29

step-by-step explanation:

his first public project he is asked to create a small scale drawing. the garden is a right triangle with base 25m and height 30m. are you trying to solve for the last side/hypotenuse? the irrational form of the answer would be 5\sqrt{61}