How many atoms of carbon are contained in 47.6 of al2(co3)3?

Step-by-step explanation:

How many atoms of carbon are contained in 47.6 g of Al2(CO3)3? The molar mass of Al2(CO3)3 is 233.99 g/mol.

(47.6g molc) x (1 mol molc/ 233.99g) x (3 mol C/1 mol molc)

x (6.022*10E23 atoms/ 1 mol C)

= 3.675*10E23

or

step-by-step explanation:

we need to solve for 'x' the following equation:  

we have that:

⇒

⇒ ⇒

factorizing, we get that:

  ⇒

then, the solutions are: or

nothing extraneous has been found!