The hypotenuse of a 45°-45°-90° triangle measures 128 cm.
What is the length of one leg of the triangle?
64 cm
642 cm
D
128 cm
128V2 cm

64cm

Step-by-step explanation:

A squared + B squared = C squared this is the formula, c is the hypotenuse, so A+B=128

64+64+128

idk

B: 64 square root 2 cm

Step-by-step explanation:

This is correct on edge 2020

(x+3)(x+7)

step-by-step explanation:

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°