A rectangular box has a length of 8 feet and a width of 2 feet. The length of the three-dimensional diagonal is 10 feet. What is the height of the box?

please answer

Step-by-step explanation:

Observe the picture attached.

Find the value of "x" and "y" using the Pythagoren Theorem:

If you solve for "a":

Where "a" is the hypotenuse and "b" and "c" are the legs.

In this case, for "x" you know that:

Then, the value of "x" is:

For "y" you can see that:

Subsituting values and solving for h, you get:

quit

step-by-step explanation:

to find the perimeter of the rectangle this is the expression:

x-9+x-9+3x-4+3x-4=138

if we simplify it:

8x-26=138

remember, 138 is what it all adds up to

the length is 11.5cm

the width is 57.5cm

the area is 661.25cm^2

the answers might not be correct use at own risk